Given a circle with radius πr and a square with side length a. We have the formula for the area of the circle and square as follows:

• Circle: ~S_c~ = π~r^2~
• Square: ~S_s~ = ~a^2~

In which: π = 3.14159265359

Your task is to compare the areas of the two shapes and give the result according to the following rule:

• If the area of the circle is larger than the area of the square → print "Circle"
• If the area of the circle is smaller than the area of the square → print "Square"
• If the areas are equal → print "Equal"

Input: Input from the standard device has the following format:

• The first line contains an integer t (1 ≤ t ≤ 10) - the number of data sets to be checked.
• The next t lines, each line contains two integers r and a:
  • r is the radius of the circle (1 ≤ r ≤ ~10^{18}~)
  • a is the side of the square (1 ≤ a ≤ ~10^{18}~)

Output: Write to the standard device, for each data set, print out a line containing the result on each line with the value "Circle", "Square" or "Equal" according to the problem requirements.

Exam:

Input

3
10 18
10 6
7 7

Output

Square
Circle
Circle

Explain

• Set 1: Circle is bigger than square → "Circle"
• Set 2: Circle is smaller than square → "Square"
• Set 3: Circle is still bigger than square → "Circle"